Factorise:
(i) $7 (2 x + 5) + 3 (2 x + 5)$
(ii) $5 a (2 x + 3 y) - 2 b (2 x + 3 y)$

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Solution

We have,
(i) $7 (2 x + 5) + 3 (2 x + 5) = (7 + 3) (2 x + 5)$
[Taking ( $2 x + 5)$ common]
$= 10 (2 x + 5)$
(ii) $5 a (2 x + 3 y) - 2 b (2 x + 3 y) = (2 x + 3 y) (5 a - 2 b)$ [Taking $(2 x + 3 y)$ common]

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