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Question

Factorise :

(i) a2ab3a+3b(ii) x2yxy2+5x5y(iii) a2ab(1b)b3(iv) xy2+(x1)y1(v) (ax+by)2+(bxay)2(vi) ab(x2+y2)xy(a2+b2)(vii) m1(m1)2+ama

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Solution

(i) a2ab3a+3b=a(ab)3(ab)=(ab)(a3)(ii) x2yxy2+5x5y=xy(xy)+5(xy)=(xy)(xy+5)(iii) a2ab(1b)b3=a2ab+ab2b3=a(ab)+b2(ab)=(ab)(a+b)2(iv) xy2+(x1)y1=xy2+xyy1=xy(y+1)1(y+1)=(xy1)(y+1)(v) (ax+by)2+(bxay)2=a2x2+b2y2+2abxy+b2x2+a2y22abxy=a2x2+b2y2+b2x2+. y2a2x2+a2y2+b2x2+b2y2a2(x2+y2)+b2(x2+y2)=(x2+y2)(a2+b2)(vi) ab(x2+y2)xy(a2+b2)=abx2+aby2a2xyb2xy=abx2a2xy+aby2b2xy=abx2a2xyb2xy+aby2=ax(bxay)by(bxay)=(bxay)(axby)(vii) m1(m1)2+ama=(m1)(m1)2+a(m1)=(m1)(1(m1)+a)=(m1)(1m+1+a)=(m1)(2m+a)


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