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Question

Factorise
(i) a4b4 (ii) p481 (iii) x4(y+z)4 (iv) x4(xz)4 (v) a42a2b2+b4

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Solution

i)a4b4=(a2b2)(a2+b2)=(a+b)(ab)(a2+b2)=(a+b)(a2+b2)(ab)ii)p481=(p29)(p2+9)=(p+3)(p3)(p2+9)iii)x4(y+z)4=(x2(y+z)2)(x2+(y+z)2)=(x+y+z)(xyz)(x2+(y+z)2)iv)x4(xz)4=(x2(xz)2)(x2+(xz)2)=(x+xz)(xx+z)(x2+(xz)2)=(2xz)(z)(x2+(xz)2)v)a42a2b2+b4=a4a2b2a2b2+b4=a2(a2b2)b2(a2b2)=(a2b2)2=(a+b)2(ab)2

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