wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise :
(i)ax+bx+ay+by
(ii)ax2+by2+bx2+ay2
(iii)a2+bc+ab+ac
(iv)axay+bxby

Open in App
Solution

We have,
(i) ax + bx + ay + by = (ax + bx) + (ay + by) [Grouping the terms]
= (a + b)x + (a + b)y
= (a + b) (x + y) [Taking (a + b) common]
(ii) ax2+by2+bx2+ay2=ax2+bx2+ay2+by2 [Re-arranging the terms]
=(a+b)x2+(a+b)y2=(a+b)(x2+y2) [Taking (a + b) common]
(iii) a2+bc+ab+ac=(a2+ab)+(ac+bc) [Re-grouping the terms]
=a(a+b)+(a+b)c=(a+b)(a+c) [Taking (a + b) common]
(iv)axay+bxby=a(xy)+b(xy)
=(a+b)(xy) [Taking (x – y) common]

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation Using Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon