Question

Factorise it $\frac{1}{16}{x}^2-\frac{1}{169}$.

Answer 1

$$\begin{array}{c}\frac{x^2}{{\left(4\right)}^2}-\frac{1}{{\left(13\right)}^2}\\ {\left(\frac{x}{4}\right)}^2-{\left(\frac{1}{13}\right)}^2\left[a^2-b^2=\left(a-b\right)\left(a+b\right)\right]\\ \left(\frac{x}{4}-\frac{1}{13}\right)\left(\frac{x}{4}+\frac{1}{13}\right)\end{array}$$