Question

Factorise it:-

(n - 10)² + (10 - n)

Answer 1

Given (n – 10)^2 + (10 – n)
= (10 – n)^2 + (10 – n)
We can change n-10 is 10-n because negative inside the bracket is cancel by squaring

= (10 – n)[(10 – n) + 1]

= (10 – n)(11 – n)

OR

(n-10)^2+(10-n)
⇒(n^2-20n+100)+(10-n)
⇒n^2-21n+110