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Expansion of (x^2 - y^2)

Factorise : ...

Question

Factorise : $(l + m)^{2} - 4 l m$

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Solution

${(l + m)}^{2} - 4 l m$
$= l^{2} + m^{2} + 2 l m - 4 l m$
$= l^{2} + (2 l m - 4 l m) + m^{2}$
$= l^{2} - 2 l m + m^{2}$
$= {(l - m)}^{2}$

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