Factorise :
$p^{2} - 10 p + 24$

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Solution

To Factorise $\to p^{2} - 10 p + 24$

By splitting the middle term,
$= p^{2} - 6 p - 4 p + 24$
$= p (p - 6) - 4 (p - 6)$
$= (p - 4) (p - 6)$

So, $p^{2} - 10 p + 24 = (p - 4) (p - 6)$

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p^{2} - 10 p + 25 = 0

Question 1(ii)
Factorise the following expressions
$p^{2} - 10 p + 25$

p^{2} + 10 p + 24 = 0

p^{2} - 10 p + 16

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