Factorise $p^{2} + 6 p - 16$

(p + 8) (p - 2)

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(p - 8) (p - q)

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(p + 8) (p - 1)

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(p + 8) (p - 7)

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Solution

The correct option is A $(p + 8) (p - 2)$
$p^{2} + 6 p - 16$
$= p^{2} + 8 p - 2 p - 16$
$= p (p + 8) - 2 (p + 8)$
$= (p + 8) (p - 2)$

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p^{2} + 8 p + 16

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(p + 8) (p - 3)

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