Factorise $p^{2} + 6 p + 8$

(p + 2) (p - 2)

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(p + 4) (2 p - 2)

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(2 p + 4) (p + 2)

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(p + 4) (p + 2)

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Solution

The correct option is D $(p + 4) (p + 2)$
$p^{2} + 6 p + 8$
$= p^{2} + 4 p + 2 p + 8$
$= p (p + 4) + 2 (p + 4)$
$= (p + 4) (p + 2)$

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(p^{2} - 4 p + 5, 2) = (2 p - 3, | p - 2 |)

p

(p^{2} - 4 p + 5, 2) = (2 p - 3, | p - 2 |)

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p^{2} + 6 p - 16

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