Factorise:
px-5q+pq-5x

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Solution

px + pq – 5q – 5x

px + pq – 5q – 5x

= p(x + q) – 5 (q + x)

= (x + q) (p – 5)

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Similar questions

(9 p - 5 q)^{2} + 180 p q = (9 p + 5 q)^{2}

Question 5(ii)
Show that:
$(9 p - 5 q)^{2} + 180 p q = (9 p + 5 q)^{2}$

(9 p - 5 q)^{2} + 180 p q

3 p^{2} = 5 p + 2

3 q^{2} = 5 q + 2

p \neq q

p q

p^{2} + 25 q^{2} = 634

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