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Question

Factorise q2−10q+21

A
(q7)(q3)
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B
(q2)(q4)
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C
(q1)(q5)
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D
(q9)(q2)
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Solution

The correct option is C (q7)(q3)
Consider, q210q+21
=q27q3q+21
=q(q7)3(q7)
=(q7)(q3)

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