Factorise- - 3 a 2 -2a-5- 3

The given expression #160; √( 3 ) a^ 2 +2a 5√( 3 ) #160;can be factorised as follows: √( 3 ) a^ 2 +2a 5√( 3 ) =√( 3 ) a^ 2 +5a 3a 5√( 3 ) =a(√( 3 ) ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation Using Algebraic Identities

Factorise: √...

Question

Factorise:
$\sqrt{3} a^{2} + 2 a - 5 \sqrt{3}$

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Solution

The given expression $\sqrt{3} a^{2} + 2 a - 5 \sqrt{3}$ can be factorised as follows:

$\sqrt{3} a^{2} + 2 a - 5 \sqrt{3} = \sqrt{3} a^{2} + 5 a - 3 a - 5 \sqrt{3} = a (\sqrt{3} a + 5) - \sqrt{3} (\sqrt{3} a + 5) = (\sqrt{3} a + 5) (a - \sqrt{3})$

Hence, $\sqrt{3} a^{2} + 2 a - 5 \sqrt{3} = (\sqrt{3} a + 5) (a - \sqrt{3})$

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Factorise:√3a2+2a−5√3

The given expression √3a2+2a−5√3 can be factorised as follows:√3a2+2a−5√3=√3a2+5a−3a−5√3 =a(√3a+5)−√3(√3a+5)=(√3a+5)(a−√3)Hence, √3a2+2a−5√3=(√3a+5)(a−√3)

Factorise:
$\sqrt{3} a^{2} + 2 a - 5 \sqrt{3}$