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Question

Factorise :
(i) x2+8x+16
(ii) 4a24a+1

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Solution

We have,
(i) x2+8x+16=x2+2×x×4+42
=(x+4)2 [Using :a2+2ab+b2=(a+b)2]
=(x+4)(x+4)
(ii) 4a24a+1=(2a)22×2a×1+(1)2
=(2a1)2 [Using :a22ab+b2=(ab)2]
=(2a1)(2a1)

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