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Question

Factorise the expression:
2a3−3a2b+2a2c

A
a2(2a3b+2c)
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B
a2(2a+3b+2c)
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C
a2(2a3b2c)
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D
None of these
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Solution

The correct option is A a2(2a3b+2c)
2a33a2b+2a2c

Taking a2 common from all 3 terms

=a2(2a3b+2c)

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