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Question

Factorise the expression 2x3b2−4x5b4

A
2x2b2(12x2b2)
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B
2x2b3(12x2b2)
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C
2x3b3(12x2b2)
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D
2x3b2(12x2b2)
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Solution

The correct option is D 2x3b2(12x2b2)
The given expression is 2x3b24x5b4
Taking out the common factor 2x3b2 we get,
2x3b2(12x2b2)

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