Factorise the expression 2 x 3 b 2-4 x 5 b 4A- 2x3b21-2x2b2B- 2x2b21-2x2b2C- 2 - 2 b 31-2 x 2 b 2D- 2 - 3 b 31-2 x 2 b 2

The correct option is A 2x3b2(1 2x2b2)The given expression is nbsp;2x^3b^2 4x^5b^4 Taking out the common factor 2x^3b^2 we get, 2x^3b^2(1 2x^2b^2) nbsp; ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation by Common Factors

Factorise the...

Question

Factorise the expression $2 x^{3} b^{2} - 4 x^{5} b^{4}$

2 x^{3} b^{2} (1 - 2 x^{2} b^{2})

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2 x^{2} b^{2} (1 - 2 x^{2} b^{2})

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2 x^{2} b^{3} (1 - 2 x^{2} b^{2})

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2 x^{3} b^{3} (1 - 2 x^{2} b^{2})

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Solution

The correct option is A $2 x^{3} b^{2} (1 - 2 x^{2} b^{2})$
The given expression is $2 x^{3} b^{2} - 4 x^{5} b^{4}$
Taking out the common factor $2 x^{3} b^{2}$ we get,
$2 x^{3} b^{2} (1 - 2 x^{2} b^{2})$

Suggest Corrections

Factorise the expression 2x3b2−4x5b4

The correct option is A 2x3b2(1−2x2b2)The given expression is 2x3b2−4x5b4 Taking out the common factor 2x3b2 we get, 2x3b2(1−2x2b2)

Factorise the expression $2 x^{3} b^{2} - 4 x^{5} b^{4}$

The correct option is A $2 x^{3} b^{2} (1 - 2 x^{2} b^{2})$
The given expression is $2 x^{3} b^{2} - 4 x^{5} b^{4}$
Taking out the common factor $2 x^{3} b^{2}$ we get,
$2 x^{3} b^{2} (1 - 2 x^{2} b^{2})$