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Question

Factorise the expression: 2y2−4y−30

A
(y5)(y+3)
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B
(y+5)(y3)
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C
(y+6)(y4)
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D
2(y5)(y+3)
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Solution

The correct option is D 2(y5)(y+3)
2y24y30

=2(y22y15) .... taking out the common factor 2
=2(y25y+3y15) .... =2[y(y5)+3(y5)]
=2(y5)(y+3)

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