Factorise the expression $4 x^{2} + 20 x - 96$

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Solution

We notice that 4 is the common factor of all the terms.
Thus $4 x^{2} + 20 x - 96 = 4 [x^{2} + 5 x - 24]$
Now consider $x^{2} + 5 x - 24$
$= x^{2} + 8 x - 3 x - 24$
$= x (x + 8) - 3 (x + 8)$
$= (x + 8) (x - 3)$
Therefore $4 x^{2} + 20 x - 96 = 4 (x + 8) (x - 3)$

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Factorise the expression 4x2+20x−96

We notice that 4 is the common factor of all the terms.Thus 4x2+20x−96=4[x2+5x−24]Now consider x2+5x−24=x2+8x−3x−24=x(x+8)−3(x+8)=(x+8)(x−3)Therefore 4x2+20x−96=4(x+8)(x−3)

Factorise the expression $4 x^{2} + 20 x - 96$

We notice that 4 is the common factor of all the terms.
Thus $4 x^{2} + 20 x - 96 = 4 [x^{2} + 5 x - 24]$
Now consider $x^{2} + 5 x - 24$
$= x^{2} + 8 x - 3 x - 24$
$= x (x + 8) - 3 (x + 8)$
$= (x + 8) (x - 3)$
Therefore $4 x^{2} + 20 x - 96 = 4 (x + 8) (x - 3)$