Factorise the expression: $a m^{2} + b m^{2} + b n^{2} + a n^{2}$

(m^{2} + n^{2}) (a + b)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(m^{2} - n^{2}) (a + b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(m^{2} + n^{2}) (a - b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(m^{2} + n^{2}) (2 a + b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(m^{2} + n^{2}) (a + b)$
$a m^{2} + b m^{2} + b n^{2} + a n^{2}$
$= (a m^{2} + b m^{2}) + (b n^{2} + a n^{2})$
$= (a + b) m^{2} + (b + a) n^{2}$
$= (a + b) (m^{2} + n^{2})$

Suggest Corrections

Similar questions

a m^{2} + b m^{2} + b n^{2} + a n^{2}

a m^{2} + b m^{2} + b n^{2} + a n^{2}

a m^{2} + b m^{2} + b n^{2} + a n^{2}

a m^{2} + b m^{2} + b n^{2} + a n^{2}

l x + m y + n = 0

a x^{2} + 2 h x y + b y^{2} = 1

P

Q

P Q

n^{2} (a + b) = l^{2} + m^{2}

Join BYJU'S Learning Program