Factorise the expression and divide them as directed.
$(5 p^{2} - 25 p + 20) \div (p - 1)$ .

Open in App

Solution

$5 p^{2} - 25 p + 20$

$= 5 p^{2} - 5 p - 20 p + 20$

$= 5 p (p - 1) - 20 (p - 1)$

$= (p - 1) (5 p - 20)$

Now, $(5 p^{2} - 25 p + 20) \div (p - 1)$

$= \frac{(p - 1) (5 p - 20)}{(p - 1)}$

$= 5 p - 20$

$= 5 (p - 4)$

Suggest Corrections

Similar questions

(5 p^{2} - 25 p + 20) \div (p - 1)

(5 p^{2} - 25 p + 20) \div (p - 1)

5 p q (p^{2} - q^{2}) \div 2 p (p + q)

(5 p^{2} - 25 p + 20) \div (p - 1)

(y^{2} + 7 y + 10) \div (y + 5)

(m^{2} - 14 m - 32) \div (m + 2)

(5 p^{2} - 25 p + 20) \div (p - 1)

4 y z (z^{2} + 6 z - 16) \div 2 y (z + 8)

(5 p q (p^{2} - q^{2}) \div 2 p (p + q)

12 x y (9 x^{2} - 16 y^{2}) \div 4 x y (3 x + 4 y)

39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)

Join BYJU'S Learning Program