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Question

Factorise the expression: (x−2y+3z)2

A
x2+y2+9z24xy+12yz+6zx
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B
x2+y2+9z24y12yz+6zx
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C
x2+4y2+9z24xy12yz+5zx
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D
x2+4y2+9z24xy12yz+6zx
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Solution

The correct option is D x2+4y2+9z24xy12yz+6zx
(x2y+3z)2
Using,(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
=x2+(2y)2+(3z)2+2×x×(2y)+2×(2y)×3z+2×3z×x
x2+4y2+9z24xy12yz+6zx

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