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Question

Factorise the expression:
x4+y4−3x2y2.

A
(x2+y2+xy)(x2y2+xy)
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B
(x2y2+xy)(x2y2+xy)
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C
(x2y2xy)(x2+y2+xy)
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D
(x2y2+xy)(x2y2xy)
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Solution

The correct option is D (x2y2+xy)(x2y2xy)
Given, the expression is
x4+y43x2y2.
the above expression can be written as,
(x2)2+(y2)22x2y2x2y2
=(x2)22x2y2+(y2)2x2y2
Using the identity
(ab)2=a22ab+b2,we get,
(x2y2)2(xy)2
[Using identity: a2b2=(ab)(a+b)]
=(x2y2+xy)(x2y2xy)

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