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Question

Factorise the following.
256a8b8.

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Solution

(2a)8(b)8[{(2a)}2]2{b4}2[a2b2=(a+b)(ab)]{(2a)4b4}{(2a)4+b2}[{(2a)2}2(b2)](16a4+64){(2a)2b2}{(2a)2+b2}(16a4+b4)(2ab)(2a+b)(4a2+b2)(16a4+b4)

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