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Question

Factorise the following: −27x3+y3−z3−9xyz

A
(3x+yz)(9x2y2z2+3xy+yz3xz)
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B
(3x+yz)(9x2+y2+z2+xy+yz3xz)
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C
(3x+yz)(9x2+y2+z2+3xy+yz3xz)
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D
(y3z)(9x2+y+z2+3xy+y3z)
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Solution

The correct option is C (3x+yz)(9x2+y2+z2+3xy+yz3xz)
27x3+y3z39xyz
Using, a3+b3+c33abc=(a+b+c)(a2+b2+c2abacbc)
=(3x)3+y3+(z3)3(3x)(y)(z)
=(3x+yz)((3x)2+y2+(z)2(3x)y(3x)(z)y(z))
=(3x+yz)(9x2+y2+z2+3xy3xz+yz)

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