Factorise the following:
$2 x^{2} - 7 x - 15$

(x + 3) (x + 4)

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(2 x + 3) (x + 5)

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(2 x + 3) (x - 5)

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(x - 2) (x - 8)

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Solution

The correct option is C $(2 x + 3) (x - 5)$
$2 x^{2} - 7 x - 15$
$= 2 x^{2} - 10 x + 3 x - 15$
$= 2 x (x - 5) + 3 (x - 5)$
$= (x - 5) (2 x + 3)$

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