Factorise the following:
$3 a^{3} - 3 a$

a (2 a + 1) (a + 1)

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3 a (a + 1) (a - 1)

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3 a (a - 4) (3 a - 1)

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a (a + 1) (a - 1)

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Solution

The correct option is B $3 a (a + 1) (a - 1)$
$3 a^{3} - 3 a$
$= 3 a (a^{2} - 1)$
$= 3 a (a + 1) (a - 1)$ (Using $a^{2} - b^{2} = (a + b) (a - b)$ )

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