Factorise the following:
$6 x^{2} + 7 x - 3$

(3 x - 1) (x + 3)

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(3 x + 1) (x + 3)

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(3 x - 1) (2 x + 3)

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(3 x + 1) (2 x - 3)

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Solution

The correct option is B $(3 x - 1) (2 x + 3)$
$6 x^{2} + 7 x - 3$
$= 6 x^{2} + 9 x - 2 x - 3$
$= 3 x (2 x + 3) - 1 (2 x + 3)$
$= (2 x + 3) (3 x - 1)$

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