Factorise the following:
$6 x^{2} - 7 x y - 13 y^{2}$

(x + 7 y) (x - 3 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + y) (6 x - 13 y)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x - y) (7 x - 2 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x - 2 y) (x - 7 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(x + y) (6 x - 13 y)$
$6 x^{2} - 7 x y - 13 y^{2}$
$= 6 x^{2} - 13 x y + 6 x y - 13 y^{2}$
$= x (6 x - 13 y) + y (6 x - 13 y)$
$= (6 x - 13 y) (x + y)$

Suggest Corrections

Similar questions

Factorise the following using appropriate identities:
$9 y^{2} - 6 y + 1$

-

x^{2} - 14 x y + 49 y^{2}

(x - 7 y) (x - 7 y)

x^{5} y^{5} + x^{3} y^{3} + x^{2} y^{2}

(x - 2 y) (x - 2 y) =

Join BYJU'S Learning Program