Factorise the following.
$8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}$

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Solution

$((2 a)^{3} - b^{3}) - (12 a^{2} b - 6 a b^{2}) = (2 a - b)^{3} + 3 \cdot 2 a \cdot b (2 a - b) - 6 a b (2 a - b) = (2 a - b) [(2 a - b)^{2} + 6 a b - 6 a b] = (2 a - b)^{3}$

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8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}

Factorise : 8a³ + b³ + 12a²b + 6ab²

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

Factorise: $8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}$

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