Factorise the following: $8 x^{3} + 125 y^{3}$

(2 x + 5 y) (4 x^{2} - 5 x y + 25 y^{2})

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(2 x + 5 y) (4 x^{2} - 10 x y + 25 y^{2})

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(2 x + 5 y) (4 x^{2} + 10 x y + 25 y^{2})

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(2 x + 5 y) (4 x^{2} + 5 x y + 25 y^{2})

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Solution

The correct option is B $(2 x + 5 y) (4 x^{2} - 10 x y + 25 y^{2})$
$8 x^{3} + 125 y^{3}$
Using, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$
$= (2 x)^{3} + (5 y)^{3}$
$= (2 x + 5 y) [(2 x^{2}) - (2 x) (5 y) + (5 y^{2})]$
$= (2 x + 5 y) (4 x^{2} - 10 x y + 25 y^{2})$

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Similar questions

4 x^{2} - 25 y^{2} + 2 x + 5 y

4 x^{2} + 5 y = 6 + 20 x y - 25 y^{2} + 2 x, 7 x - 11 y = 17

4 x^{2} + 5 y = 6 + 20 x y - 25 y^{2} + 2 x

7 x - 11 y = 17

49 x^{2} - 25 y^{2}

State True or False

(−2x+5y−3z)² = 4x²+25y²+9z²−20xy−30yz+12zx

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