Factorise the following:
$a^{2} - 12 a b + 36 b^{2} - 25$ .

(a + 3 b + 5) (a + 6 b - 5)

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(a - 3 b + 5) (a - 6 b - 5)

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(a + 2 b - 5) (a - 6 b + 5)

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(a - 6 b + 5) (a - 6 b - 5)

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Solution

The correct option is D $(a - 6 b + 5) (a - 6 b - 5)$
$a^{2} - 12 a b + 36 b^{2} - 25$
$= a^{2} - 2 \times a \times 6 b + (6 b)^{2} - 5^{2}$
$= (a - 6 b)^{2} - 5^{2}$
$= (a - 6 b + 5) (a - 6 b - 5)$

Suggest Corrections

Similar questions

(\frac{5 a}{6 b} + \frac{6 b}{5 a})

\frac{25 a^{2}}{36 b^{2}} - 2 + \frac{36 b^{2}}{25 a^{2}}

25 a^{2} - 36 b^{2}

5 a + 3 b, a - 2 b, 3 a + 5 b

9 a + 6 b

:

= 2 : 5

(3 a + 4 b) : (5 a + 6 b)

a : b = 2 : 5

(3 a + 4 b) : (5 a + 6 b)

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