Factorise the following:
$(a + b) (c + d) - a^{2} + b^{2}$

(a - 2 b) (c + d + a + b)

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(a + b) (c - d - a - b)

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(a - b) (c + d + a - b)

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(a + b) (c + d - a + b)

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Solution

The correct option is C $(a + b) (c + d - a + b)$
$(a + b) (c + d) - a^{2} + b^{2}$
$= (a + b) (c + d) - (a^{2} - b^{2})$
$= (a + b) (c + d) - (a + b) (a - b)$
$= (a + b) [(c + d) - (a - b)]$
$= (a + b) (c + d - a + b)$

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Similar questions

2 (a b + c d) - a^{2} - b^{2} + c^{2} + d^{2}

If $\frac{a}{b}$ = $\frac{c}{d}$ , then which of the following is true

\frac{a}{b}

\frac{c}{d}

A \equiv (a, b)

B \equiv (c, d)

c > a > 0

d > b > 0

C

x -

A C + B C

(a + b) (c + d) $-$ a² + b²

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