Question

Factorise the following by grouping the terms:
h) $9x^3+6x^2{y}^2–4y^3–6xy$

Answer 1

Given: $9x^3+6x^2{y}^2–4y^3–6xy$

$=9x^3+6x^2{y}^2–6xy–4y^3$

On grouping the terms, we get,

$=(9x^3+6x^2{y}^2)–(6xy+4y^3)$

$=3x^2(3x+2y^2)–2y(3x+2y^2)$

$=(3x+2y^2)(3x^2–2y)$

Hence, the answer is $(3x+2y^2)(3x^2–2y)$.