Question

Factorise the following by grouping the terms:
m) $p^2{x}^2+(p{x}^2+1)x+p$

Answer 1

Given: $p^2{x}^2+(p{x}^2+1)x+p$

$=p^2{x}^2+p{x}^3+x+p$

On grouping the terms, we get,

$=(p^2{x}^2+p{x}^3)+(p+x)$

$=p{x}^2(p+x)+1(p+x)$

$=(p+x)(p{x}^2+1)$

Hence, the answer is $(p+x)(p{x}^2+1)$.