Question

Factorise the following by taking out the common factors:
a) $4x^2{y}^3-6x^3{y}^2-12x{y}^2$

Answer 1

Given: $4x^2{y}^3-6x^3{y}^2-12{xy}^2$

The common factor is $2x{y}^2$

Dividing by $2x{y}^2$ in the above expression :

We get,

$\left\{\frac{4x^2{y}^3}{2x{y}^2}\right\}$ –$\left\{\frac{6x^3{y}^2}{2x{y}^2}\right\}$– $\left\{\frac{12x{y}^2}{2x{y}^2}\right\}$

$=2xy-3x^2-6$

$\therefore 4x^2{y}^3-6x^3{y}^2-12x{y}^2=2x{y}^2(2xy–3x^2–6)$