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Question
Factorise the following:
e) (2p+q)2−10p−5q−6
e) (2p+q)2−10p−5q−6
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Solution
Given: (2p+q)2−10p−5q−6
=(2p+q)2−5(2p+q)−6
By splitting the middle term, we get,
=(2p+q)2−6(2p+q)+1(2p+q)−6
=(2p+q)(2p+q−6)+1(2p+q−6)
=(2p+q−6)(2p+q+1)
Hence, the answer is (2p+q−6)(2p+q+1).
=(2p+q)2−5(2p+q)−6
By splitting the middle term, we get,
=(2p+q)2−6(2p+q)+1(2p+q)−6
=(2p+q)(2p+q−6)+1(2p+q−6)
=(2p+q−6)(2p+q+1)
Hence, the answer is (2p+q−6)(2p+q+1).
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