Factorise the following equation:
$4 x^{2} + 20 x + 25$

(2 x - 5)^{2}

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(x + 5)^{2}

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(2 x + 5)^{2}

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(x - 5)^{2}

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Solution

The correct option is B $(2 x + 5)^{2}$
$4 x^{2} + 20 x + 25$
Using $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
$= {(2 x)}^{2} + 5^{2} + 2 \times 2 x \times 5$
$= (2 x + 5)^{2}$

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