Factorise the following expression:
$16 z + 20 z^{3}$

4 z (2 - 5 z^{2})

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4 z (4 + 5 z)

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4 z (4 + 5 z^{2})

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4 z (2 + 5 z^{2})

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Solution

The correct option is D $4 z (4 + 5 z^{2})$
$16 z + 20 z^{3}$
Taking common factor 4z from both the terms we get,
$= 4 z (4 + 5 z^{2})$

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Factorise the polynomial $14 (3 y - 5 z)^{3} + 7 (3 y - 5 z)^{2}$

- 16 z + 20 z^{3}

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