Factorise the following expression: 2x3+2xy2+2xz2
Factorise the given expression by splitting the like terms
Given, 2x3+2xy2+2xz2
The like term in the expression is 2x
So, upon separating the like terms, the factorisation will be 2x(x2+y2+z2)
Hence, the factorisation of 2x3+2xy2+2xz2 will be 2x(x2+y2+z2).
Using the FActor theroem, show that: (i) (x-2) is a factor fo x3−2x2−9x+18 Hence factories the expression (ii) (x+5) is a factor of2x3+5x2−28x−15 Hence factorise fthe expression 2x3+5x2−28x−18 completely. (iii) (3x+2) is a factor fo 3x3+2x2−3x−2. Hence factorise the expression 3x3+2x2−3x−2 completely