Factorise the following expression: ax2y+bxy2+cxyz
Factorise by separating the like term(s)
Given, ax2y+bxy2+cxyz
=xy(ax+by+cz)
Therefore, factorisation of ax2y+bxy2+cxyz will be xy(ax+by+cz).
Factorise the following expressions
(i) 7x − 42
(ii) 6p − 12q
(iii) 7a2 + 14a
(iv) −16z + 20z3
(v) 20l2m + 30 alm
(vi) 5x2y − 15xy2
(vii) 10a2 − 15b2 + 20c2
(viii) −4a2 + 4ab − 4 ca
(ix) x2yz + xy2z + xyz2
(x) ax2y + bxy2 + cxyz
Factories the following expressions.(i) 7x−42