Factorise the following expressions:
$a x^{2} y + b x y^{2} + c x y z$

xy(ax + by + cz)

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axy(x + by + cz)

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bxy(ax + y + cz)

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xy(ax + by - cz)

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Solution

The correct option is A xy(ax + by + cz)
$a x^{2} y + b x y^{2} + c x y z$
In the above expression, the common factor is $= x y$
$∴$ $a x^{2} y + b x y^{2} + c x y z$ = $x y (a x + b y + c z)$

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Factorisation of a x^{2} y + b x y^{2} + c x y z gives:

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