Factorise the following expressions:
$p^{2} + 6 p + 8$

(p - 2) (p + 4)

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(p + 2) (p + 4)

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(p + 2) (p - 4)

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(p - 2) (p - 4)

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Solution

The correct option is D $(p + 2) (p + 4)$
$p^{2} + 6 p + 8$
$= p^{2} + 2 p + 4 p + 8$
$= p (p + 2) + 4 (p + 2)$
$= (p + 2) (p + 4)$

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