Factorise the following : (i) 25a Square + 30a + 9

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Solution

25a²+30a+9

We factorise using splitting the middle term formula.

So we need to find 2 numbers whose sum = 30
And product = 9×25=225

Then numbers are 15 and 15 .... simple mind calculation...nubers sum's last digit is zero and product last digit is 5...so numbers will be multiple of five...

Then 25a²+15a+15a+9
5a(5a+3)+3(5a+3)
Take out the common term (5a+3)

(5a+3)(5a+3)

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Similar questions

9 x^{2} + 6 x + 1 - 25 y^{2}

a^{2} + b^{2} + 2 a b 2 b c + 2 c a

25 m^{2} + 30 m + 9

(25 a^{2} + 16 b^{2} + 9 + 40 a b - 24 b - 30 a)

a = - 1

b = 2

Factorise:

$25 a^{2} - 9 b^{2}$

Question 92 (viii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{2}}{9} - \frac{y^{2}}{25}$

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