Factorise the following numbers into primes.
(i) 342
(ii) 377
(iii) 559

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Solution

(i)
$342 = 2 \times 171$
$= 2 \times 3 \times 57$
$= 2 \times 3 \times 3 \times 19$
(ii)
$377 = 13 \times 29$
(iii)
$559 = 13 \times 43$

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Factorise the following numbers into primes. (i) 342 (ii) 377 (iii) 559

(i) 342=2×171 =2×3×57 =2×3×3×19 (ii) 377=13×29 (iii) 559=13×43

Factorise the following numbers into primes.
(i) 342
(ii) 377
(iii) 559

(i)
$342 = 2 \times 171$
$= 2 \times 3 \times 57$
$= 2 \times 3 \times 3 \times 19$
(ii)
$377 = 13 \times 29$
(iii)
$559 = 13 \times 43$