Question

Factorise the following trinomials:
$9d^2-6d+1$

Answer 1

Given, $9d^2-6d+1$

$=9d^2-3d-3d+1$

$=3d(3d-1)-1(3d-1)$

$=(3d-1)(3d-1)$

Hence the factors of $9d^2-6d+1$ are $(3d-1)$ and $(3d-1)$.