Consider the given expression,
⇒4y2−4y+1
⇒(2y)2−2.2y+12
We know that,
A2−2AB+B2=(A−B)2
So,(2y)2−2.2y+12=(2y−1)2
Hence, this is the answer.
Factorise the following using appropriate identities: 4y2–4y+1
Factorise the following using appropriate identities: 9y2–6y+1