Factorise the following using appropriate identities: [1 MARK]
$4 y^{2} - 4 y + 1$

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Solution

Formula: 0.5 Mark
Application: 0.5 Mark

$4 y^{2} - 4 y + 1$

$= {(2 y)}^{2} - 2 (2 y) (1) + 1^{2}$

comparing with above identity ${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$

$= {(2 y - 1)}^{2}$

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