Factorise the following using appropriate identities: $9 x^{2} + 6 x y + y^{2}$

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Solution

Identity: $(a + b)^{2} = a^{2} + 2 a b + b^{2}$
$9 x^{2} + 6 x y + y^{2} = (3 x)^{2} + 2 (3 x) (y) + y^{2} = (3 x + y)^{2}$

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Factorise the following using appropriate identities: [4 MARKS]
$1) 9 x^{2} + 6 x y + y^{2}$
$2) 4 y^{2} - 4 y + 1$

9 x^{2} + 6 x y + y^{2}

4 y^{2} - 4 y + 1

x^{2} - \frac{y^{2}}{100}

9 x^{2} + 6 x y + y^{2}

4 x^{2} - \frac{y^{2}}{25}

Factorise:
$9 x^{2} + 6 x y + y^{2}$

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