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Byju's Answer
Standard IX
Mathematics
Remainder Theorem
Factorise the...
Question
Factorise the polynomial:
x
2
−
1
+
2
a
x
+
a
2
A
(
x
−
a
−
1
)
(
x
+
a
−
1
)
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B
(
x
+
a
+
1
)
(
x
+
a
−
1
)
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C
(
x
+
a
+
1
)
(
x
−
a
+
1
)
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D
(
x
−
a
+
1
)
(
x
+
a
−
1
)
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Solution
The correct option is
C
(
x
+
a
+
1
)
(
x
+
a
−
1
)
We have,
x
2
−
1
+
2
a
x
+
a
2
⇒
x
2
+
2
a
x
+
a
2
−
1
⇒
(
x
+
a
)
2
−
1
∵
(
x
+
y
)
2
=
x
2
+
2
x
y
+
y
2
⇒
(
x
+
a
)
2
−
1
2
⇒
(
x
+
a
+
1
)
(
x
+
a
−
1
)
∵
x
2
−
y
2
=
(
x
+
y
)
(
x
−
y
)
Hence, this is the answer.
Suggest Corrections
0
Similar questions
Q.
Write each of the following in the simplest form:
(i)
cot
-
1
a
x
2
-
a
2
,
x
>
a
(ii)
tan
-
1
x
+
1
+
x
2
,
x
∈
R
(iii)
tan
-
1
1
+
x
2
-
x
,
x
∈
R
(iv)
tan
-
1
1
+
x
2
-
1
x
,
x
≠
0
(v)
tan
-
1
1
+
x
2
+
1
x
,
x
≠
0
(vi)
tan
-
1
a
-
x
a
+
x
,
-
a
<
x
<
a
(vii)
tan
-
1
x
a
+
a
2
-
x
2
,
-
a
<
x
<
a
(viii)
sin
-
1
x
+
1
-
x
2
2
,
-
1
<
x
<
1
(ix)
sin
-
1
1
+
x
+
1
-
x
2
,
0
<
x
<
1
(x)
sin
2
tan
-
1
1
-
x
1
+
x
Q.
If
tan
−
1
{
x
a
+
√
a
2
−
x
2
}
=
1
p
sin
−
1
x
a
,
−
a
<
x
<
a
.
find the value of p.
Q.
How many of the following statements are correct?
1.
∫
1
√
a
2
−
x
2
d
x
=
1
a
sin
−
1
(
x
a
)
+ c
2.
∫
1
|
x
|
√
x
2
−
1
d
x
=
sec
−
1
(
x
)
+ c
___
Q.
If two factors of a 2nd degree polynomial are (x-1) and (x-2), then the polynomial can be obtained by __.
Q.
The integral
∫
x
cos
−
1
(
1
−
x
2
1
+
x
2
)
d
x
, where
x
>
0
, is equal to
(where
c
is constant of integration)
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